How do you solve #7/4z - 1/6 = 17/6 + 3/4z#?

1 Answer
sankarankalyanam
Apr 27, 2018

#color(blue)(z = 3#

Explanation:

#(7/4)z - 1/6 = 17 / 6 + (3/4)z#

#(7/4)z - (3/4)z = 17 / 6 + 1/6, " bringing like terms together"#

#((7 - 3) / 4) z = (17 + 1) / 6, " combining terms using common denominator"#

#(cancel4/cancel4)z = (cancel(18)^color(red)(3) /cancel 6)#

#color(blue)(z = 3#

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