How do you solve #7 s - 2/3 - 3s - 16/6 = 2#?

1 Answer
Jul 26, 2016

Answer:

#color(green)(s=4/3)#

Explanation:

Group variable terms on the left and constant terms on the right
#color(white)("XXX")7s-3s=2+2/3+(cancel(16)^8)/(cancel(6)_3)#

Simplify both sides:
#color(white)("XXX")4s=6/3+2/3+8/3=16/3#

Divide both sides by #4# to reduce the left side to a unit variable
#color(white)("XXX")s=4/3#