How do you solve $7^(x – 2) = 12^x$ ?

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Answer 1 · 2016-04-12T09:50:31

$x=(2 log 7)/(log 7-log 12)=-7.22$ , nearly.

Use $log (a^m)=m log a$ .

Equating the logarithms,

$(x-2) log 7=x log 12$ .
So, $x (log 7-log 12)=2 log 7. x=(2 log 7)/(log 7-log 12)$

How do you solve 7^(x – 2) = 12^x7^(x – 2) = 12^x?