How do you solve #7/y-7/3=1/4#?

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Answer 1 · 2018-03-15T13:10:54

#y=84/31#

First we add the #7/3# to both sides giving us
#7/"y"=1/"4"+7/"3"#

#1/"4" + 7/"3" = 31/12#

You can this by finding common denominators, like so
#"(3)1"/"(3)4" + "(4)7"/"(4)3"#

Which gives us
#3/12+28/12 = 31/12#

So now that we have
#7/y=31/12#

We can cross multiply, which gives us
#31y=7(12)#

#31y=84#

Finally divide #31# on both sides, giving us
#y=84/31#