Question

How do you solve `72-26y=2y^2` by factoring?

Answer 1

Do a little regrouping

`72−26y=2y^2`

`=-2y^2 +72 - 26 y = 0`

`=(y^2 - 13 y + 36 )= 0/-2= 0`

`= (y−4)(y−9)=0`

Hence possible Solutions are y = 4 , y = 9