# How do you solve 72-26y=2y^2 by factoring?

Mar 27, 2015

Do a little regrouping

72−26y=2y^2

$= - 2 {y}^{2} + 72 - 26 y = 0$

$= \left({y}^{2} - 13 y + 36\right) = \frac{0}{-} 2 = 0$

 = (y−4)(y−9)=0

Hence possible Solutions are y = 4 , y = 9