How do you solve #(7t + 7)/4 + (7t + 8)/3 = 33#?

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Answer 1 · 2015-11-29T02:59:09

#t=7#

Multiply both sides by #12# because #4# and #3# are factors of #12#

#12((7t+7)/4+(7t+8)/3)=33(12)#

#3(7t+7)+4(7t+8)=396#

Distribute the #3# and #4#

#21t+21+28t+32=396#

Combine like terms

#49t+53=396#

Subtract #53# from both sides

#49t=343#

Divide both sides by #49#

#t=7#

Now check to see if #t=7# gives #33#

#(7(7)+7)/4+(7(7)+8)/3=33#

#(49+7)/4+(49+8)/3=33#

#56/4+57/3=33#

#14+19=33#