How do you solve #7y + 2( y - 2) = 6( y + 1) - 3#?

2 Answers
Apr 4, 2018

Answer:

#y=3#

Explanation:

#7y+2*(y-2)=6*(y+1)-3#

#7y+2y-6=6y+6-3#

#9y-6=6y+3#

#3y=9#

#y=3#

Apr 4, 2018

Answer:

Put all the y on one side of the equation, all numbers on the other.

Explanation:

#7*y+2*(y−2)=6*(y+1)−3#

Multiply the parenthesis.

#7*y+2*y+2*(-2)=6*y+6-3#
#7*y+2*y-4=6*y+6-3#
#9*y-4=6*y+3#

Subtract 6y, and add 4.

#9*y-6*y-4+4=6*y-6*y+3+4#
#9*y-6*y=3+4#
#3*y=7#

Divide with 3.

#y=7/3#