How do you solve #8( 12- 2x ) = 5x + 12#?

3 Answers

Answer:

#x = 4#

Explanation:

Multiply out the brackets

#8 xx 12 = 96#

#8 xx (-2x) = -16x#

to give

#96 - 16x#

on the left side of the equation. Therefore

#96 - 16x = 5x + 12#

Then rearrange the whole equation to get all the #x#'s on one side of the equation.

Add #16x# to both sides of the equation to eliminate the #-16x# from the left side, and minus #12# from both sides to eliminate the #+12# from the right side. This means all the #x#'s are on the left side.

#96 - 12 = 5x +16x#

#84 = 21x#

Divide both sides of the equation by #21# to get the #x# term on its own.

#84/21 = (21x)/21#

Therefore

#x = 4#

In order to ensure the #x# term is correct, be sure to sub it back into the original equation to make sure it works.

Jun 17, 2018

Answer:

By opening up the bracket

Explanation:

#8(12-2x)=5x+12#

#96-16x=5x+12#

So

# 21x=84#

# x=4#

Jun 17, 2018

Answer:

Simplifying for x gives us: 4

Explanation:

To start solving this, we need to distribute the 8 to the left side of the equal sign to simplify it.

So distributing the 8 on the left side, gives us: #96-16x#

So we have #96-16x=5x+12#

We can do a couple of things of subtracting #x# on both sides or numbers on both sides. Let's subtract 5x from both sides which gives us:

#96-21x=12#

Now, let subtract 96 to both sides which gives us:

#-21x=-84#

We can divide both sides by -21 which gives us: 4.