How do you solve $8 (3^{6 - x}) = 40$ $8(3^(6-x))=40$ ?

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Answer 1 · 2018-05-24T11:15:47

$6 - {log}_{3} 5 = x$ $6 - log_3 5 = x$

$3^{6 - x} = 5$ $3^{6 - x} = 5$

$6 - x = {log}_{3} 5$ $6 - x = log_3 5$

$6 - {log}_{3} 5 = x$ $6 - log_3 5 = x$

How do you solve 8(3^(6-x))=408(36−x)=408(3^(6-x))=40?