# How do you solve 8-3/8k=-4?

Feb 16, 2017

$k = 32$

#### Explanation:

$8 - \frac{3}{8} k = - 4$

or

$\frac{3}{8} k = 8 + 4$

or

$\frac{3}{8} k = 12$

or

$k = 12 \times \frac{8}{3}$

or

$k = 32$

Feb 16, 2017

See the entire solution process below:

#### Explanation:

Step 1) Subtract $\textcolor{red}{8}$ from each side of the equation to isolate the $k$ term while keeping the equation balanced:

$- \textcolor{red}{8} + 8 - \frac{3}{8} k = - \textcolor{red}{8} - 4$

$0 - \frac{3}{8} k = - 12$

$- \frac{3}{8} k = - 12$

Step 2) Multiply each side of the equation by $- \frac{\textcolor{red}{8}}{\textcolor{b l u e}{3}}$ to solve for $k$ while keeping the equation balanced:

$- \frac{\textcolor{red}{8}}{\textcolor{b l u e}{3}} \times - \frac{3}{8} k = - \frac{\textcolor{red}{8}}{\textcolor{b l u e}{3}} \times - 12$

$- \frac{\cancel{\textcolor{red}{8}}}{\cancel{\textcolor{b l u e}{3}}} \times - \frac{\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{3}}}}{\textcolor{red}{\cancel{\textcolor{b l a c k}{8}}}} k = - \frac{\textcolor{red}{8}}{\textcolor{b l u e}{3}} \times - \left(3 \times 4\right)$

$k = - \frac{\textcolor{red}{8}}{\cancel{\textcolor{b l u e}{3}}} \times - \left(\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{3}}} \times 4\right)$

$k = 32$