How do you solve #8(3a-b) + 4(2b-a)#?

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Answer 1 · 2018-06-18T15:13:36

See a solution process below:

To simplify this expression, first eliminate the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(8)(3a - b) + color(blue)(4)(2b - a) =>#

#(color(red)(8) xx 3a) - (color(red)(8) xx b) + (color(blue)(4) xx 2b) - (color(blue)(4) xx a) =>#

#24a - 8b + 8b - 4a#

Next, group like terms:

#24a - 4a - 8b + 8b#

Now, combine like terms:

#(24 - 4)a + (-8 + 8)b =>#

#20a + 0b =>#

#20a#