# How do you solve 8- 3r \leq 5- 2r?

Dec 14, 2016

$r \ge 3$

#### Explanation:

First, do the necessary arithmetic to isolate the $r$ term on one side of the inequality and the constants on the other side of the inequality:

$8 - 3 r + 3 r - 5 \le 5 - 5 - 2 r + 3 r$

$8 - 0 - 5 \le 0 - 2 r + 3 r$

$8 - 5 \le r$

$3 \le r$

To get this solution in terms of $r$ we need to reverse or "flip" the inequality:

$r \ge 3$