# How do you solve (8-3x)/4=32?

Dec 7, 2016

$x = - 40$

#### Explanation:

In $\frac{\textcolor{b l u e}{\left(8 - 3 x\right)}}{4} = 32$ , you need to isolate the part that contains $x$

To get rid of the 4 in the denominator, multiply both sides by 4:

$\frac{\cancel{4} \times \textcolor{b l u e}{\left(8 - 3 x\right)}}{\cancel{4}} = 4 \times 32$

$8 \textcolor{red}{- 3 x} = 128 \text{ } \leftarrow$ now isolate the x-term

$- 3 x = 128 - 8$

$- 3 x = 120 \text{ }$ divide both sides by -3.

$\frac{- 3 x}{-} 3 = \frac{120}{-} 3$

$x = - 40$