# How do you solve 8 (4u - 1) - 12u = 11 (2u - 6)?

Sep 27, 2015

You would begin by distributing the term outside of you parentheses and then combining your like terms.

#### Explanation:

1. $8 \left(4 u - 1\right) - 12 u = 11 \left(2 u - 6\right)$
2. $8 \cdot 4 u$
3. $8 \cdot - 1$
4. Left side should now look like this: $32 u - 8 - 12 u$
5. Right side:
6. $11 \cdot 2 u$
7. $11 \cdot - 6$
8. Right side should now look like this: $22 u - 66$
9. Combine like terms and simplify:
10. $32 u - 8 - 12 u = 22 u - 66$
11. $32 u - 12 u = 20 u$
12. $20 u - 8 = 22 u - 66$
13. Subtract $22 u$ from both sides to combine and get $- 2 u$
14. Add $66$ to both sides so that way the $66$ on the right side cancels out and you get $58$ on the left side.
15. Final answer: $- 2 u + 58$