How do you solve #8 (4u - 1) - 12u = 11 (2u - 6)#?

1 Answer
Sep 27, 2015

Answer:

You would begin by distributing the term outside of you parentheses and then combining your like terms.

Explanation:

  1. #8(4u-1)-12u=11(2u-6)#
  2. #8*4u#
  3. #8*-1#
  4. Left side should now look like this: #32u -8 -12u#
  5. Right side:
  6. #11*2u#
  7. #11*-6#
  8. Right side should now look like this: #22u-66#
  9. Combine like terms and simplify:
  10. #32u-8-12u=22u-66#
  11. #32u-12u=20u#
  12. #20u-8=22u-66#
  13. Subtract #22u# from both sides to combine and get #-2u#
  14. Add #66# to both sides so that way the #66# on the right side cancels out and you get #58# on the left side.
  15. Final answer: #-2u+58#