How do you solve #8= 5- 4p#?

1 Answer
May 10, 2018

#p=-3/4#

Explanation:

#8=5-4p#

Let's take away anything on the right side, that doesn't have a "p" attached.
#8\color(red)(-5)=\cancel(5)\cancel(\color(red)(-5))-4p#
Simplify: #3=-4p#

Now take away anything on the right side... that isn't a variable. In other words, isolate the variable.
#3\color(blue)(\div(-4))=\cancel(-4)p\cancel(\color(blue)(\div(-4)))#
Simplify: #-3/4=p#