Question

How do you solve `8^(-5a)-5=53`?

Answer 1

`a=-0.391`

Explanation:

`8^(-5a)-5=53`

`hArr8^(-5a)=53+5=58`

ot `log_8(58)=-5a`

or `a=-1/5xxlog_8(58)=-1/5xxlog58/log8`

i.e. `a=-1/5xx1.763428/0.90309=-0.391`