How do you solve #-8/63b = -4/5#?
1 Answer
Mar 9, 2016
Explanation:
'Attach'the b to the 8 as shown.
# (8b)/63 = 4/5# now 'cross multiply'
#(8bxx5) = (4xx63) rArr 40b = 252 # divide both sides by 40
#(cancel(40)b)/cancel(40) = 252/40 rArr b = 63/10#
