Question

How do you solve `-8( 6k - 2) = 400`?

Answer 1

Answer:

`k=-8`

Explanation:

`-8(6k-2)=400`

Multiply the bracket by `-8`

`-48k + 16 =400`

Subtract `16` from both sides

`-48 k =384`

Divide both sides by `-48`

`k= -8`

Answer 2

Answer:

`k= -8`

Explanation:

1) Apply the operation on the brackets, so `-8` will be multiplied with the variable `(6k)` and the constant `(-2)`

`-48k +16 = 400" "` (`-` multiplied by `-` is `+`)

2) Separate the variables and the constants. So, we will keep `-48k` on the left-hand side of the `=` and bring `16` to the right-hand side of the `=`. The sign of `16` will change to `-`.

`-48k = 400-16`

`-48k = 384`

3) Since term `-48k` is equivalent to `-48 * k`, both sides must be divided by `-48` as to move this to the right-hand side

`(-48k)/(-48) = 384/-48`

`k = -8 " "` (since `+` divided by `-` is `-`)