# How do you solve -8( 6k - 2) = 400?

Mar 11, 2018

$k = - 8$

#### Explanation:

$- 8 \left(6 k - 2\right) = 400$

Multiply the bracket by $- 8$

$- 48 k + 16 = 400$

Subtract $16$ from both sides

$- 48 k = 384$

Divide both sides by $- 48$

$k = - 8$

Mar 11, 2018

$k = - 8$

#### Explanation:

1) Apply the operation on the brackets, so $- 8$ will be multiplied with the variable $\left(6 k\right)$ and the constant $\left(- 2\right)$

$- 48 k + 16 = 400 \text{ }$ ($-$ multiplied by $-$ is $+$)

2) Separate the variables and the constants. So, we will keep $- 48 k$ on the left-hand side of the $=$ and bring $16$ to the right-hand side of the $=$. The sign of $16$ will change to $-$.

$- 48 k = 400 - 16$

$- 48 k = 384$

3) Since term $- 48 k$ is equivalent to $- 48 \cdot k$, both sides must be divided by $- 48$ as to move this to the right-hand side

$\frac{- 48 k}{- 48} = \frac{384}{-} 48$

$k = - 8 \text{ }$ (since $+$ divided by $-$ is $-$)