How do you solve #-8( 6k - 2) = 400#?

2 Answers
Mar 11, 2018

Answer:

#k=-8#

Explanation:

#-8(6k-2)=400#

Multiply the bracket by #-8#

#-48k + 16 =400#

Subtract #16# from both sides

#-48 k =384#

Divide both sides by #-48#

#k= -8#

Mar 11, 2018

Answer:

#k= -8#

Explanation:

1) Apply the operation on the brackets, so #-8# will be multiplied with the variable #(6k)# and the constant #(-2)#

# -48k +16 = 400" "# (#-# multiplied by #-# is #+#)

2) Separate the variables and the constants. So, we will keep #-48k# on the left-hand side of the #=# and bring #16# to the right-hand side of the #=#. The sign of #16# will change to #-#.

#-48k = 400-16#

#-48k = 384#

3) Since term #-48k# is equivalent to #-48 * k #, both sides must be divided by #-48# as to move this to the right-hand side

#(-48k)/(-48) = 384/-48#

#k = -8 " "# (since #+# divided by #-# is #-#)