How do you solve $8 (7 x - 1) + 8 x = 376$ $8( 7x - 1) + 8x = 376$ ?

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How do you solve $8 (7 x - 1) + 8 x = 376$ $8( 7x - 1) + 8x = 376$ ?

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Answer 1 · 2018-04-02T14:12:30

$x = 6$ $x = 6$

Explanation:

$8 (7 x - 1) + 8 x = 376$ $8( 7x - 1) + 8x = 376$
$8 \times 7 x - 8 \times 1 + 8 x = 376$ $8 xx 7x - 8 xx 1 + 8x = 376$
$56 x - 8 + 8 x = 376$ $56x - 8 + 8x = 376$
$64 x = 384$ $64x = 384$
$x = \frac{384}{64}$ $x = 384/64$
$x = 6$ $x = 6$

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How do you solve $8 (7 x - 1) + 8 x = 376$ $8( 7x - 1) + 8x = 376$ ?

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How do you solve 8(7x−1)+8x=3768( 7x - 1) + 8x = 376?

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How do you solve $8 (7 x - 1) + 8 x = 376$ $8( 7x - 1) + 8x = 376$ ?