# How do you solve 8(y-5)+2y=-10?

Jul 2, 2016

$y = 3$

#### Explanation:

Multiply out the bracket and collect like terms.

$8 y - 40 + 2 y = - 10$

$10 y = - 10 + 40 = 30$

Divide both sides by 10.

$y = 3$

(Just to check we have obtained the correct answer, sub back into the original equation)

$8 \left(3 - 5\right) + 2 \left(3\right) = - 16 + 6 = - 10$

So our solution works!