How do you solve #8p+7(1+2p)=-147#?

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Answer 1 · 2016-12-20T13:32:47

#p = -7#

The first step is to expand the term in parenthesis:

#8p + (7 xx 1) + (7 xx 2p) = -147#

#8p + 7 + 14p = -147#

Next, group the #p# terms:

#8p + 14p + 7 = -147#

#(8 + 14)p + 7 = -147#

#22p + 7 = -147#

Now, isolate the #p# term while keeping the equation balanced:

#22p + 7 - color(red)(7) = -147 - color(red)(7)#

#22p + 0 = -154#

#22p = -154#

Now we can solve for #p#:

#(22p)/22 = (-154)/22#

#(color(red)(cancel(color(black)(22)))p)/color(red)(cancel(color(black)(22))) = -7#

#p = -7#