# How do you solve 8r + 4(2r - 6) = 4r - 4?

Mar 19, 2016

$= \frac{5}{3}$
$\implies 8 r + 8 r - 24 = 4 r - 4$
$\implies 16 r - 4 r = 24 - 4 = 20$
$\implies 12 r = 20$
$r = \frac{20}{12} = \frac{5}{3}$