How do you solve #-8v + 4( v - 2) = - 32#?

2 Answers
Apr 13, 2017

Answer:

#v=6#

Explanation:

Multiply #4# through the brackets,

#-8v+4v-8=-32#

Collect like terms,

#-4v=-24#

Divide both sides by #-4#,

#v=6#

Apr 13, 2017

Answer:

#v=6#

See the process in the explanation.

Explanation:

Solve:

#-8v+4(v-2)=-32#

Expand.

#-8v+4v-8=-32#

Add #8# to both sides of the equation.

#-8v+4v-color(red)cancel(color(black)(8))+color(red)cancel(color(black)(8))=-32+8#

Simplify.

#-4v=-24#

Divide both sides by #-4#.

#color(red)cancel(color(black)(-4v))/color(red)cancel(color(black)(-4))=color(red)cancel(color(black)(-24))^color(blue)6/color(red)cancel(color(black)(-4)^color(blue)1#

Simplify.

#v=6#