# How do you solve (8x + 1) ( 5x - 7) = 0?

Apr 17, 2017

$x = - \frac{1}{8} \mathmr{and} \frac{7}{5}$

#### Explanation:

Because two terms are multiplied to equal 0, one of the terms must be 0.

So we set each term equal to 0, and simplify.
$8 x + 1 = 0$
$8 x = - 1$
$x = - \frac{1}{8}$

or...
$5 x - 7 = 0$
$5 x = 7$
$x = \frac{7}{5}$