# How do you solve 8x-2-5x+7=1x+5?

Jul 27, 2018

$x = 0$

#### Explanation:

$8 x - 2 - 5 x + 7 = 1 x + 5$

Simplify the left side by combining like terms:

$3 x + 5 = x + 5$

Subtract $\textcolor{b l u e}{x}$ from both sides:
$3 x + 5 \quad \textcolor{b l u e}{- \quad x} = x + 5 \quad \textcolor{b l u e}{- \quad x}$

$2 x + 5 = 5$

Subtract $\textcolor{b l u e}{5}$ from both sides:
$2 x + 5 \quad \textcolor{b l u e}{- \quad 5} = 5 \quad \textcolor{b l u e}{- \quad 5}$

$2 x = 0$

Divide both sides by $\textcolor{b l u e}{2}$:
$\frac{2 x}{\textcolor{b l u e}{2}} = \frac{0}{\textcolor{b l u e}{2}}$

$x = 0$

Hope this helps!