How do you solve #8x-2-5x+7=1x+5#?

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Answer 1

Jul 27, 2018

#x = 0#

#8x - 2 - 5x + 7 = 1x + 5#

Simplify the left side by combining like terms:

#3x + 5 = x + 5#

Subtract #color(blue)x# from both sides:
#3x + 5 quadcolor(blue)(-quadx) = x + 5 quadcolor(blue)(-quadx)#

#2x + 5 = 5#

Subtract #color(blue)5# from both sides:
#2x + 5 quadcolor(blue)(-quad5) = 5 quadcolor(blue)(-quad5)#

#2x = 0#

Divide both sides by #color(blue)2#:
#(2x)/color(blue)2 = 0/color(blue)2#

#x = 0#

Hope this helps!