Question

How do you solve `(9)^(2k) = (3^5)^k`?

Answer 1

k = 0

Explanation:

`(9)^(2k) = (3^5)^k`

`(3^2)^(2k) = (3)^(5*k)`

`(3)^(2*2k) = (3)^(5k)`

`(3)^(4k) = (3)^(5k)`

`4k = 5k \implies k = 0`