How do you solve #-9=(-4+m)/2#?

2 Answers
Dec 22, 2016

Answer:

#m = -14#

Explanation:

First, multiply each side of the equation by #2# to eliminate the fraction and to keep the equation balanced. Eliminating the fraction will make the problem easier to work with:

#color(red)(2) xx -9 = color(red)(2) xx (-4 + m)/2#

#-18 = color(red)(cancel(color(black)(2))) xx (-4 + m)/color(red)(cancel(color(black)(2)))#

#-18 = -4 + m#

Now, we can isolate the #m# term and solve for #m#:

#-18 + color(red)(4) = -4 + m + color(red)(4)#

#-14 = -4 + 4 + m#

#-14 = 0 + m#

#-14 = m#

Dec 22, 2016

Answer:

#m= -14#

Explanation:

Given
#color(white)("XXX")-9=(-4+m)/2#

If we multiply both sides by #2# we can get rid of the fraction on the right side:
#color(white)("XXX")-9color(blue)(xx2) =(-4+m)/cancel(2)color(blue)(xxcancel(2))#

#color(white)("XXX")-18=-4+m#

Now adding #4# to both sides will isolate the constant on one side and the variable on the other side:
#color(white)("XXX")-18color(red)( + 4) =cancel(-4)+mcolor(red)(+cancel(4))#

#color(white)("XXX")-14=m#

or (in the more common order)
#color(white)("XXX")m= -14#