How do you solve #9/k - 7 = 6/k#?
1 Answer
Jan 23, 2016
Explanation:
Collect variable terms to 'left hand side' of equation.
ie
# 9/k - 6/k = 7# ( the fraction has a common denominator so subtract numerators )
# 3/k = 7/1 # 'cross multiply' to obtain 7k = 3
(divide both sides by 7 )
#(cancel(7) k)/cancel(7) = 3/7 rArr k = 3/7 #
