How do you solve #-9(x-3)^2=-7#?

1 Answer
Mar 13, 2018

Answer:

#x = 3 pm sqrt(7)/3 #

Explanation:

We need to solve for x. In order to isolate x, we first need to isolate the parenthesis:
#(x-3)^2 = (-7) / -9 = 7/9 #
Next, we want to undo the squaring, so
#(x-3) = pm sqrt(7/9) #
Then we can add the 3 to get x alone:
#x = 3 pm sqrt(7)/3 #

Since it is a second degree equation, the two values (plus and minus) makes sense.