How do you solve #[9/(x-5)] – 1 = [8/(x+5)]#?

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Answer 1 · 2016-08-04T10:15:06

The Soln. #x=11, or, x=-10#

#9/(x-5)-1=8/(x+5)#

#rArr 9/(x-5)-8/(x+5)=1#.

#rArr (9(x+5)-8(x-5))/{(x-5)(x+5)}=1#

#rArr (x+85)/(x^2-25)=1#

#rArrx+85=x^2-25#

#rArr x^2-x-110=0#

#rArr (x-11)(x+10)=0#

Hence, the Soln. #x=11, or, x=-10#