How do you solve #9c(c-11)+10(5c-3)=3c(c+5)+c(6c-3)-30#?
The answer is: undetermined/impossible.
First you want to distribute to all of the parentheses:
Then you want to combine like factors.
Now that you have like factors on both sides, you can work to getting "c" by itself on one side.
^^^However, the equation above is impossible because no matter what number you put (besides 0), you will not get the same answer from both sides.
-49 is not equal to 12,
so impossible or undetermined.