# How do you solve 9e^(1.4p-10)-10=17?

Jun 14, 2018

$p = \setminus \frac{\ln \left(3\right) + 10}{1.4}$

#### Explanation:

Add $10$ to both sides:

$9 {e}^{1.4 p - 10} = 27$

divide both sides by $9$:

${e}^{1.4 p - 10} = 3$

consider the natural logarithm of both sides, leveraging the fact that $\ln \left({e}^{x}\right) = x$

$1.4 p - 10 = \ln \left(3\right)$

Add $10$ to both sides:

$1.4 p = \ln \left(3\right) + 10$

Divide both sides by $1.4$:

$p = \setminus \frac{\ln \left(3\right) + 10}{1.4}$