# How do you solve 9x^2 - 21x + 10 = 0?

Jun 13, 2015

#### Answer:

By factoring the left side we can get $x = \frac{5}{3}$ or $x = \frac{2}{3}$

#### Explanation:

Given $9 {x}^{2} - 21 x + 10$
the left side can be factored to give
$\textcolor{w h i t e}{\text{XXXX}}$$\left(3 x - 5\right) \left(3 x - 2\right) = 0$
which implies either
$\textcolor{w h i t e}{\text{XXXX}}$$3 x - 5 = 0 \Rightarrow x = \frac{5}{3}$
or
$\textcolor{w h i t e}{\text{XXXX}}$$3 x - 2 = 0 \Rightarrow x = \frac{2}{3}$