How do you solve #9x^2 -2x +4=10x#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer maganbhai P. Mar 4, 2018 #x=3/2# Explanation: We know that, #color(red)(a^2-2ab+b^2=(a-b)^2)# So, #9x^2-2x+4=10x# #rArr9x^2-12x+4=0# #rArr(3x)^2-2(3x)(2)+(2)^2=0# #rArr(3x-2)^2=0# #rArr(3x-2)=0# #rArr3x=2# #x=3/2# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1238 views around the world You can reuse this answer Creative Commons License