How do you solve #9x-8=x^2#?

1 Answer
May 2, 2018

Answer:

#x=1" or "x=8#

Explanation:

#"express the equation in "color(blue)"standard form"#

#•color(white)(x)ax^2+bx+c=0#

#"subtract "9x-8" from both sides"#

#rArrx^2-9x+8=0larrcolor(blue)"in standard form"#

#"the factors of + 8 which sum to - 9 are - 1 and - 8"#

#rArr(x-1)(x-8)=0#

#"equate each factor to zero and solve for x"#

#x-1=0rArrx=1#

#x-8=0rArrx=8#