How do you solve #(9y)/14 + 3/7- =9/14#?

2 Answers
Mar 19, 2016

Answer:

#y=0,bar(3)#

Explanation:

#(9y)/14=9/14-3/7#

#(9y)/cancel(14)=((7*9)-(3*14))/(cancel(14)*7)#

#y=((7*9)-(3*14))/(9*7)#
#y=(63-42)/63#
#y=0,bar(3)#

Mar 19, 2016

Answer:

y = #1/3#

Explanation:

#(9y)/14 + 3/7 = 9/14#

Firstly change all denominators to 14 g
giving
#(9y)/14 +6/14 = 9/14#
Now you can ignore the denominators to get
9y + 6 = 9
Subtract 6 from both sides
9y = 3
Divide both sides by 9
y = #3/9#
which simplifies to
y = #1/3#