How do you solve #(a+1)(a+2) = 0# by factoring?

1 Answer
Aug 17, 2015

Answer:

The solutions are
#color(blue)(a=-1,a=-2#

Explanation:

#(a+1)(a+2)=0# is already the factorised form of the equation
#a^2+3a+2#

Since we have the factorised form we simply equate the factors to the number on the R.H.S and obtain the solutions.

#(a+1)(a+2)=0#

Solution 1:
#a+1=0, color(blue)(a=-1#

Solution 2
#a+2=0, color(blue)(a=-2#