# How do you solve (a+1)(a+2) = 0 by factoring?

Aug 17, 2015

The solutions are
color(blue)(a=-1,a=-2

#### Explanation:

$\left(a + 1\right) \left(a + 2\right) = 0$ is already the factorised form of the equation
${a}^{2} + 3 a + 2$

Since we have the factorised form we simply equate the factors to the number on the R.H.S and obtain the solutions.

$\left(a + 1\right) \left(a + 2\right) = 0$

Solution 1:
a+1=0, color(blue)(a=-1

Solution 2
a+2=0, color(blue)(a=-2