How do you solve #a^2+a-30=0#?
Find 2 numbers knowing sum (-1) and product (-30). Roots have opposite signs.
Factor pairs of (-30) --> ....(-3, 10)(-5, 6). This sum is 1 = b.
Then the 2 real roots are the opposite:
Factor the trinomial into two binomials. Set each binomial equal to zero and solve for
Find two numbers that when added equal