How do you solve #a/5-2=9#?

1 Answer
Feb 14, 2017

See the entire solution process below:

Explanation:

Step 1) Add #color(red)(2)# to each side of the equation to isolate the #a# term while keeping the equation balanced:

#a/5 - 2 + color(red)(2) = 9 + color(red)(2)#

#a/5 - 0 = 11#

#a/5 = 11#

Step 2) Multiply each side of the equation by #color(red)(5)# to solve for #a# while keeping the equation balanced:

#color(red)(5) xx a/5 = color(red)(5) xx 11#

#cancel(color(red)(5)) xx a/color(red)(cancel(color(black)(5))) = 55#

#a = 55#