How do you solve abs(10+7x)>=11?

2 Answers
Mar 19, 2017

{x<=-3" or "x>=1/7}

Explanation:

"The expression of |10+7x| may be positive or negative"

"if negative : " -(10+7x)>=11

-10-7x>=11

-7x>=11+10

-7x>=21

-x>=21/7

-x>=3

x<=-7

"if positive : "

10+7x>=11

7x>=11-10

7x>=1

x>=1/7

Mar 19, 2017

x>=1/7" or " x<=-3

Explanation:

This inequality is of the form.

|x|>=arArrxcolor(red)(>=)a" or " xcolor(red)(<=)-a

There are 2 possible solutions here.

10+7xcolor(red)(>=)11" or " 10+7xcolor(red)(<=)-11

color(blue)"Solving " 10+7x>=11

subtract 10 from both sides.

cancel(10)cancel(-10)+7x>=11-10

rArr7x>=1

divide both sides by 7

(cancel(7) x)/cancel(7)>=1/7

rArrx>=1/7larrcolor(red)" first solution"

color(blue)"Solving " 10+7x<=-11

rArr7x<=-21

rArrx<=-3larrcolor(red)" second solution"