How do you solve #abs(14-3x)>18#?

1 Answer
Jan 24, 2017

Answer:

Solution: #x < -4/3 or x > 32/3 #
In interval notation: # ( -oo , - -4/3) uu ( 32/3 , oo) #

Explanation:

#| 14 - 3 x | > 18 or 14 - 3 x > 18 or - 3 x > 18-14 or -3 x > 4 or 3 x < -4 or x < -4/3 # OR

#| 14 - 3 x | > 18 or 14 - 3 x < -18 or - 3 x < -18-14 or -3 x < -32 or 3 x > 32 or x > 32/3 #

Solution: #x < -4/3 or x > 32/3 #
In interval notation: # ( -oo , - -4/3) uu ( 32/3 , oo) #[Ans]