How do you solve abs(2+2b)+1=3?

Jan 8, 2017

$b = 0 \text{ and } b = - 2$

Explanation:

Suppose we had :$\text{ } A + 1 = 3$

Then $A = 2$

Set $A = | 2 + 2 b | = 2$

This means that $| 2 + 2 b | = | \pm 2 | = 2$ as whatever is inside the | | is considered as positive in the answer.

Set $\textcolor{b l u e}{2 + 2 b = + 2} \textcolor{red}{\implies b = 0}$

Set $\textcolor{b l u e}{2 + 2 b = - 2} \text{ "color(green)( =>" " 2b=-2-2)" } \textcolor{red}{\implies b = - \frac{4}{2} = - 2}$