Question

How do you solve `abs(2+2b)+1=3`?

Answer 1

`b= 0" and "b=-2`

Explanation:

Suppose we had :`" "A+1=3`

Then `A=2`

Set `A=|2+2b| =2`

This means that `|2+2b|=|+-2| =2` as whatever is inside the | | is considered as positive in the answer.

Set `color(blue)(2+2b=+2)color(red)( => b=0)`

Set `color(blue)(2+2b=-2)" "color(green)( =>" " 2b=-2-2)" " color(red)(=> b=-4/2=-2)`