# How do you solve abs(2x + 1) > -3?

This is satisfied for all $x \in \mathbb{R}$ since $\left\mid y \right\mid \ge 0$ for all $y \in \mathbb{R}$.
For all $x \in \mathbb{R}$ the expression $2 x + 1$ is well defined and $\left\mid 2 x + 1 \right\mid \ge 0 > - 3$
In interval notation the solution is $x \in \left(- \infty , \infty\right)$