# How do you solve abs(2x+9) ≤ 3?

Feb 28, 2017

$- 6 \le x \le - 3$

#### Explanation:

Because it has the absolute value sign, you can assume there are two equations:
$2 x + 9 \le 3$
and
$- \left(2 x + 9\right) \le 3$

Lets solve for the first one.
$2 x \le - 6$
$x \le - 3$

Now onto the second one.
$2 x + 9 \ge - 3$
$2 x \ge - 12$
$x \ge - 6$

$x \le - 3$ and $x \ge - 6$ for $- 6 \le x \le - 3$