Question

How do you solve `abs(2x+9) ≤ 3`?

Answer 1

`-6 le x le-3`

Explanation:

Because it has the absolute value sign, you can assume there are two equations:
`2x+9le3`
and
`-(2x+9)le3`

Lets solve for the first one.
`2xle-6`
`xle-3`

Now onto the second one.
`2x+9ge-3`
`2xge-12`
`xge-6`

Now combine the two answers.
`xle-3` and `xge-6` for `-6lexle-3`