How do you solve #abs(-3r)=9#?

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Answer 1 · 2016-11-11T13:08:39

The solution to the problem is #r = 3# and #r = -3#

To solve this equation you need to solve two equations because of the absolute value signs. These equations are:

1) -3r = 9
2) -3r = -9

Solving equation 1 gives:

#-3r = 9#

#(-3r)/-3 = 9/-3#

#r = -3#

Solving equation 2 gives:

#-3r = -9#

#(-3r)/-3 = (-9)/-3#

#r = 3#