Question

How do you solve `abs((3x+2)/2)=abs((2x-3)/3)`?

Answer 1

`x in {0 , -12/5}`

Explanation:

`(3x + 2)/2 = (2x - 3)/3 or (3x + 2)/2 = -(2x - 3)/3`

`9x + 6 = 4x - 6 or 9x + 6 = -4x + 6`

`5x = -12 or 13x = 0`

`x = -12/5 or x = 0`