# How do you solve abs[5-2x] = 41?

$x \setminus \in \setminus \left\{- 18 , 23 \setminus\right\}$.
$\left\mid 5 - 2 x \right\mid = 41 \setminus \iff 5 - 2 x = 41 \mathmr{and} 5 - 2 x = - 41$.
In the first case : $- 2 x = 36 \setminus \iff x = - 18$.
In the second case : $- 2 x = - 46 \setminus \iff x = 23$.