How do you solve #abs(5n-1) = 7#? Algebra Linear Inequalities and Absolute Value Absolute Value Equations 1 Answer Sasha P. Sep 27, 2015 See the explanation. Explanation: #|5n-1|=5n-1, 5n-1>=0 <=> 5n>=1 <=> n>=1/5# #|5n-1|=-5n+1, 5n-1<0 <=> 5n<1 <=> n<1/5# We need to solve 2 equations: #5n-1=7 <=> 5n=8 <=> n=8/5>1/5# is a solution #-5n+1=7 <=> -5n=6 <=> n=-6/5<1/5# is a solution Answer link Related questions How can an absolute value equation have no solution? How can an absolute value equation have one solution? How do you solve absolute value equations? How do you solve #|x - 5| = 10#? How do you solve #8=3+|10y+5|#? How do you solve #8|x+6|=-48#? Can an absolute value equation ever have and infinite amount of solutions? What do you do when you have absolute values on both sides of the equations? How do you solve for m given #|\frac{m}{8}|=1#? How do you solve #3abs(-9 x-7)-2=13#? See all questions in Absolute Value Equations Impact of this question 1396 views around the world You can reuse this answer Creative Commons License