Question

How do you solve `abs(7+p)=7`?

Answer 1

`p=0"; "p=-14`

Explanation:

The sum inside the 'absolute' must be `+-7`
as `abs(+-7)=+7`

Thus `7+p=+-7`

Consider `" "7+p=+7 => p=0`

Consider `" "7+p=-7 => p=-14`