# How do you solve  abs(8 - 6c ) = 1?

Feb 19, 2017

$\frac{7}{6} \le c \le \frac{3}{2}$

#### Explanation:

The given equation is equivalent to:

$- 1 \le 8 - 6 c \le 1$

Let's subtract 8 and get:

$- 9 \le - 6 c \le - 7$

then change signs and inequality:

$7 \le 6 c \le 9$

and divide all terms by 6:

$\frac{7}{6} \le c \le {\cancel{9}}^{3} / {\cancel{6}}^{2}$

$\frac{7}{6} \le c \le \frac{3}{2}$